(x^2+2x+1)/(1-x)=1

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Solution for (x^2+2x+1)/(1-x)=1 equation: 


D( x )

1-x = 0

1-x = 0

1-x = 0

1-x = 0 // - 1

-x = -1 // * -1

x = 1

x in (-oo:1) U (1:+oo)

(x^2+2*x+1)/(1-x) = 1 // - 1

(x^2+2*x+1)/(1-x)-1 = 0

(x^2+2*x+1)/(1-x)+(-1*(1-x))/(1-x) = 0

x^2-1*(1-x)+2*x+1 = 0

x^2+3*x = 0

x^2+3*x = 0

x*(x+3) = 0

x+3 = 0 // - 3

x = -3

x*(x+3) = 0

(x*(x+3))/(1-x) = 0

(x*(x+3))/(1-x) = 0 // * 1-x

x*(x+3) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x )

x = 0

x in { -3, 0 }

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